PHP supports the concept of variable functions. Append parentheses to a variable and the function with the same name as whatever the variable evaluates to will be executed.
$func = ‘this_is_a_php_func’;
$func();
In the example above, $func() will be evaluated as this_is_a_php_func().
Variable functions can even be used to access class methods.
class Bar {
function __construct(){
print “Bar::__constructor()”;
}
static function test ($param1, $param2){
print “Bar::__constructor()\n”;
print “Bar::param1 : ” . $param1 .”\n”;
print “Bar::param2 : ” . $param2 .”\n”;
}
function test2 ($param1, $param2){
print “Bar::__constructor()\n”;
print “Bar::param1 : ” . $param1 .”\n”;
print “Bar::param2 : ” . $param2 .”\n”;
}
}
// access method test
$func = ‘test’;
$bar = new Bar();
$bar->$func(’aaa’,'bbbb’);
// access static method test2
$func = ‘test2′;
Bar::$func(’aaa’, ‘bbbb’);
It works for functions, will it work for class names too?
$class = “Bar”;
$func = “test2″;
$class::$func(’aaa’,'bbb’);
Unfortunately, the answer to my question was a syntax error which I initially mistook as a message from The Great Omniscient One asking me to repent.
I looked up the Hebrew for repent.
It wasn’t PHP Parse error: syntax error, unexpected T_PAAMAYIM_NEKUDOTAYIM.
Bummer.
The following, however, does work quite well.
call_user_func(array($class, $func), ‘aaa’,'bbb’)
My name is George and this is my blog.
No. Not really.
